Calculate the cyclist’s instantaneous velocity at \(35\,s.\).What was the cyclist’s velocity during the final \(10\,s\)?.What was the velocity of the cyclist during the first \(30\,s\)?.Describe the motion of the cyclist in words.The following position-time graph is for a cyclist traveling along a straight road.During its \(10\,s\) motion, what was the car’s.At what time did the car return to its starting point?.Describe, in words, the motion of the car.The graph below represents the straight line motion of a radio-controlled toy car.In which of the sections is the dancer moving with a negative velocity?.In which of the sections is the dancer moving in a positive direction?.In which of the sections ( \(A\) - \(D)\) is the dancer at rest?.What was the starting position of the dancer?.The dancer’s movements are designated by sections \(A\) to \(D.\) The graph below shows the position of a dancer moving in a straight line across a stage.as it had at point \(A.\) This is shown in the diagram below. Remember, a vector quantity has to have a magnitude and a direction. At point \(A\) the velocity was \(5\,m/s\) upward. At this point the ball has the same speed 8 8 Speed is the magnitude of the velocity vector. Point \(C\) represents the starting position. That means it is now heading downwards towards the point from which it was thrown. It is not moving, and so this is the point of maximum altitude for the ball.Īfter \(B,\) the ball has a negative velocity. At point \(B,\) the ball has zero velocity. This is the part of the graph from \(A\) to \(B\). Then the ball starts to slow down (due to gravity acting on it). Point \(A\) describes the initial velocity (upward) that the ball has. Initially the ball is thrown into the air vertically upwards (positive direction) with a speed of \(5\,m/s\). So a velocity-time graph looks like the one below. As gravity acts downwards, the velocity against time graph must have a negative gradient (because the ball is decelerating). So from the previous example, the graph of velocity against time is linear. Once the ball is thrown up, the only force acting on it is gravity which is constant. We take upwards velocity as positive and downwards velocity as negative. Ignore air resistance.įirst define the coordinate system you want to work in. Sketch and describe the graph of velocity of the ball against time from the moment it is thrown to the moment it touches the ground. A ball is thrown vertically upwards with a speed of \(5\,m/s\). Its velocity \(v\) is the gradient of the line from A to B. Looking at the graph, from A to B the object is moving at a constant velocity (because the graph is a straight line). Whereas the gradient of the distance versus time graph gave speed, the gradient of the displacement (a vector) versus time graph gives velocity (a vector). Note that this is displacement (a vector quantity) versus time.
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